profile-img
Sankar Mahato Asked a Question
September 20, 2021 10:32 pmpts 30 pts
40. For a rock that has a volume of 2 points Vim3 and density 3300kg/m3, the metal content for 60% assay value will be. V1 tonnes. (up to 2 decimal places)
  • 1 Answer(s)
  • like-1
  • 1 Likes
  • 1 Comments
  • Shares
  • Sajan sarthak Best Answer
    mass= volume*density V1 m3 * 3300 kg / m3 = V1 *3300 kg from this mass assay value of metal content = 60 % so 3300 * V1 kg * 60 /100 = 1980 V1 kg in ton 1.98* V1 ton
    Likes(0) Reply(0)
Head Office :
MPA 44, 2nd floor, Rangbari Main Road,
Mahaveer Nagar II, Kota (Raj.) – 324005

Corporate Office:
212, F-1, 2nd Floor, Evershine Tower,
Amrapali Marg,
Vaishali Nagar, Jaipur (Raj.) – 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com