Shweta thakur Asked a Question
May 6, 2021 10:25 ampts 30 pts
Problenm blem n the electrolysis of acidulated water, it is desired to obtain hydrogen at the rate ot nd at NTP condition. What should be the current passed ? I ce per second Solution. 2 H + 2 e- H Thus, 1 mole of H2, i.e., 22400 cc at NTP requires 2 F = 2 x 96500 coulombs . 1 cc at P requires 2x96500 I cc at NTP x1 =8-616C 22400 As Q=1xr . Q8-616C_ = 8-616 Ampere 1s
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  • Priyanshu kumar Best Answer
    For 1 mole of H2...when you take 2 common then at cathode reaction will be 2H+ + 2e- H2
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    Shweta thakur
    sir but reaction acidulated water main to 4 electrons aayenge Dekho book main
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