IIT JAM Follow
Himanshu Pandey Asked a Question
June 6, 2020 10:54 pm 30 pts
These questions suddenly come in my mind so I am asking bcz of curiosity ... Q.1) Why whenever we remove proportional sign a constant will come along with equal sign!!!! Q.2) Why there should be constant in indefinite integral whereas for definite integral it is not required. Also in differentiation there is no constant at all??
• 0 Likes
• Shares
• Vaishnavi rajora
I already mentioned dear.see that
• Abhishek singh
if you take definite integral, the constant if integration would come in both upper limit as well as lower limit. and get cancelled. that's why we don't write it in definite integr...
• Abhishek singh
I have shown you F1 and F2 , and their derivatives are exactly same(g1 and g2 are same) because differentiation of constant is anyways zero. Now assume, you don't know what was F1 ...
Abhishek singh
if you take definite integral, the constant if integration would come in both upper limit as well as lower limit. and get cancelled. that's why we don't write it in definite integr...
• Abhishek singh
in all the three cases, f is proportional to x. but how steeply f would increase against x is given by the proportionality constant. in first case, a large change in x results in ...
Abhishek singh
any doubts will be answered for sure. Best.
• Vaishnavi rajora
and in the answer of 2nd im with chandra sir. Suppose you are having a function f(x) which is continuous in the interval [a,b]. Let g(x) +c be the finction you got after integratin...
• Vaishnavi rajora
Suppose you find a new force, and this force happens to be proportional to the charge of the object. Then you can write: F∝Q But if you don’t know how it varies with position, o...
Vaishnavi rajora
always the sign is positive is not definate.......meaning thereby is to say that we put the constant according to our situation like in restoring force it's F= -kx here -ve sign i...
• Chandra dhawan
You don't need to put any constant at the end while evaluating a definite integral. The reason is this: Suppose you are having a function f(x) which is continuous in the interval ...