• Dinesh khalmaniya Best Answer
    option A
    • cropped6717003966223046178.jpg
    Likes(0) Reply(0)
  • Priyanshu kumar thankyou
    reshav check the exact solution
    • cropped1488100401690782185.jpg
    Likes(0) Reply(4)
    Priyanshu kumar
    Please ask if you have any doubt reshav😊
  • Dinesh khalmaniya
    hope this will help you 🙏🙏🙏
    Likes(0) Reply(1)
    Reshav
    289 to option me hi nhi h sir
  • Priyanshu kumar
    By eliminating the options given...you can clearly got the answer as the heat absorbed by cold body and heat lost by hot body...so temperature is some how between 273K and 323K....
    Likes(0) Reply(1)
    Priyanshu kumar
    Please check the attached image for exact solution...Option A is correct
  • Reshav
    sir mera 315 k aa rha hai then
    Likes(1) Reply(0)
  • Reshav
    approx bhi thk hai but itna difference
    Likes(1) Reply(0)
  • Dinesh khalmaniya
    304 he na
    Likes(0) Reply(0)
  • Dinesh khalmaniya
    approx yhi ayega
    Likes(0) Reply(0)
  • Dinesh khalmaniya
    option kya de rkha he
    Likes(0) Reply(0)
  • Amol
    Heat required to melt ice =5×80=400 cal Max. heat that can be lost by water =30×1×(323−273)=1500 cal hence, heat left after melting the ice=1100 cal Heat lost = Heat gained. (becau...
    Show more
    Likes(0) Reply(0)
Head Office :
MPA 44, 2nd floor, Rangbari main Road Mahaveer Nagar II, Kota (Raj.) - 324005

Branch Office (Jaipur):
Shyam Tower, Plot No. F2, 6th Floor Amrapali Circle,
Vaishali Nagar, Jaipur, Rajasthan 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com