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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Namrata
question 91
Dear Student,
The solution is as follows-
Total Volume = 106m 2hr .
Porosity = 10% = ({10 over 100}) = 0.1
Specific retention = 5% = ({5 over 100}) = 0.05%
P = S.Y + S.R
0.1 = S.Y + 0.05
0.1 - 0.05 = S.Y.
0.05 = S.Y.
Pumping rate = ({1000000m^{6} over 5hr}) x S.Y.
= ({1000000m^{6} over 5hr})( imes{0.05 over 100})
= 10,000 m3/