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Eduncle posted an Article
June 03, 2023 • 18:44 pm
CSIR NET Admit Card 2023: Hall Tickets Download Now

CSIR NET 2023 Admit Card will release by NTA. Know the step-by-step procedure to download CSIR NET Hall Tickets at the earliest.

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  • Hema

    Hii Eduncle... I bought study material from Eduncle ....and That was very useful.. I have cleared my exam.. I got 96.74 percentile with Air-53 Thanks 😊

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Eduncle posted an MCQ
June 02, 2023 • 11:37 am 0 points
  • CSIR NET
  • Chemical Sciences

A phase transition process is always

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    Eduncle Best Answer

    1. Phase transition cannot be isoentropic

                                    Solid ⇌liquid

                   So , entropy is going to change during phase transition

    1. Phase transition cannot be isochoric as

                        Solid ⇌gas   or    liquid  ⇌gas

                    Volume is going to change

    1. Volume is going to change

    As phase transition takes place at constant temperature and pressure

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Eduncle posted an MCQ
May 31, 2023 • 14:36 pm 0 points
  • CSIR NET
  • Mathematical Sciences

A box contains 40 numbered red balls and 60 numbered black balls. From the box. balls are drawn one by one at random without replacement till all the balls are drawn. The probabiliy that the last ball drawn is black equals?

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    Eduncle Best Answer

     Number of red balls in box = 40

    Number of black balls in box = 60

    As one ball is drawn without replacement till all balls are drawn.

    ∴Probability that last ball drawn is black = 60/100=3/5  

    Thus, option (3) is correct.

     

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Eduncle posted an Article
June 03, 2023 • 18:38 pm
CSIR NET Mathematical Sciences–Syllabus, Books, Question Papers

Crack the CSIR NET Mathematics Exam with well information about eligibility, pattern, syllabus, study material, books, questions, tips and job openings.

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    Mts Moorthi

    i am really very happy to get mathematics material. it is very useful.thanks to Eduuncle.

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Eduncle posted an Article
June 02, 2023 • 18:45 pm
CSIR NET 2023 Exam Dates & Admit Card, Application Form, Eligibility Criteria

Want to appear in NTA CSIR NET 2023 to Pursue a Career as a Lecturer or Researcher? Here is the perfect guide for you to start your preparation.

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  • Nidhi dandir

    Sir I am pass out 2016 m.sc mathematics what are career in CSIR NET

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Eduncle posted an MCQ
May 30, 2023 • 15:29 pm 0 points
  • CSIR NET
  • Mathematical Sciences

Which of the functions below is a common eigen function of d/dx and d2/dx2  operators?

Q. Which of the functions below is a common eigen function of d/dx and d2/dx2  operators?

Options

A. cos x                                B. kx

C. eix                                     D. e-x2

 

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    Eduncle Best Answer

    d2/dx2 eix=ieix

     Therefore eigen function

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Eduncle posted an Article
June 02, 2023 • 18:29 pm
CSIR NET Eligibility Criteria 2023| Age, Qualifications & Marks

CSIR NET Eligibility Criteria 2023 Exam-Age Limit, Educational Qualification, Marks & Required Degree. Check your Eligibility for the exam now.

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  • Shilpa

    I am undergoing MSc Physics in 2nd semestar which net Exam i.e UGCNet or CSIRUgC Net or any net. Which one I am elegible to Apply in Next Jun Exam 17?

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Eduncle posted an MCQ
May 29, 2023 • 12:09 pm 0 points
  • CSIR NET
  • Earth Sciences

A map is prepared on 1:50,000 scale. How many cm on the map represents 1.0 km on the ground 

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    Eduncle Best Answer

    1:50,000

    First convert 1km to cm

    1km = 1000m = 1000 × 100 cm = 1.00,000cm

    The map scale  is 1:50,000, so We divide by 50,000

    100000 ÷ 50000 = 2 Therefore,

    1km is equivalent to 2cm on the map,

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Eduncle posted an MCQ
May 28, 2023 • 17:02 pm 0 points
  • CSIR NET
  • Mathematical Sciences

Let S be the set of all integers from 100 to 999 which are neither divisible by 3 or nor divisible by 5.The number of elements in S is

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    Eduncle Best Answer

    S = {n :100 ≤ n ≤ 999 such that 3∤n and 5∤n}

    We know total number of integer from 'n' consecutive integers which are divisible by 'K' is given by nK , where [ ] denotes greatest integer function.

    Total number in elements in S

    = (Total numbers of integers from 100 to 999)- {total numbers of integers from 100 to 999 which are divisible by 3 } + (Total number of integers from 100 to 999.

    which are divisible by 5)- (Total number of integers from 100 to 999 which are divisible by 15).}

                    = 900 – 9003+9005-90015

                = 900 – 300-180+60 = 420+60=480

                    ⇒ So, option (1) is correct.

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