Akash Babu posted an Question
July 25, 2022 • 20:51 pm 30 points
  • CSIR NET
  • Mathematical Sciences

11. the general solution of the differential equation + tany tanxcosx secy is (a) 2 siny= (xtc-sinx cosx) secx (c) cosy=(x + c) sinx dy (b) siny =(x + c) cosx (

11. The general solution of the differential equation + tany tanxcosx secy is (A) 2 siny= (xtc-sinx cosx) secx (C) cosy=(x + c) sinx dy (B) siny =(x + c) coSx (D) secy (x +c) cosx

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