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Rohan Kumar posted an Question
June 23, 2020 • 10:39 am 30 points
  • CSIR NET
  • Chemical Sciences

11. wilkinson's catalyst initial proceeds as the following steps pichos pchh pichh nc a pcjho rh cho,p chp chpr pcj detemine the electron count around rh at eac

11. Wilkinson's catalyst initial proceeds as the following steps PICHos PCHh PICHh NC a PCJHo Rh CHo,P CHp CHpR PCJ Detemine the electron count around Rh at each step. (note a neufjal Rh contributes 8 valence electron)

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  • Rohan kumar Meher

    VE of Rh = 8 (mention in question),3 PPh3 = 3*2=6, 1cl=1, so total 15 e how it is 16

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    yes, but count 2 electrons for Cl because it is in -1 OS. and we are using ionic counting method

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    Dinesh khalmaniya 1 best-answer

    check the electron count in each step

    cropped81333611839295927.jpg
    eduncle-logo-app

    election count of Rh = VE of Rh + 3pph3+ 1Cl = 8 + 3(2) + 1(2) = 16

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    Lingareddy 1 best-answer

    first step +1 oxidation state 16 electrons second step +3 o.state 18 electrons third step +3 o.state 18 electrons

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    sir how it is 16 electron can you explain plz

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    rhodium have 9 electrons (cobalt group )

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