Rohan kumar Meher Asked a Question
June 23, 2020 5:09 ampts 30 pts
11. Wilkinson's catalyst initial proceeds as the following steps PICHos PCHh PICHh NC a PCJHo Rh CHo,P CHp CHpR PCJ Detemine the electron count around Rh at each step. (note a neufjal Rh contributes 8 valence electron)
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  • Dinesh khalmaniya
    in ionic method we will use 2e for Cl.
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  • Rohan kumar Meher
    VE of Rh = 8 (mention in question),3 PPh3 = 3*2=6, 1cl=1, so total 15 e how it is 16
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    Dinesh khalmaniya
    yes, but count 2 electrons for Cl because it is in -1 OS. and we are using ionic counting method
  • Dinesh khalmaniya
    hope this will help you 🙏
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  • Dinesh khalmaniya thankyou
    check the electron count in each step
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    Dinesh khalmaniya
    election count of Rh = VE of Rh + 3pph3+ 1Cl = 8 + 3(2) + 1(2) = 16
  • Lingareddy thankyou
    first step +1 oxidation state 16 electrons second step +3 o.state 18 electrons third step +3 o.state 18 electrons
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    Rohan kumar Meher
    sir how it is 16 electron can you explain plz