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Vijay posted an Question
September 28, 2022 • 01:22 am 30 points
  • CSIR NET
  • Mathematical Sciences

115. given e=1,e = 2.72,e = 7.39, e = 20.09, e = 54.60 the value of je x by numerical integration is (a) 53.873 (b) 52.873 (c) 51.873 (d) 50.873

115. Given e=1,e = 2.72,e = 7.39, e = 20.09, e = 54.60 the value of Je x by numerical integration is (a) 53.873 (b) 52.873 (c) 51.873 (d) 50.873

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  • Anonymous User best-answer

    Let f(x) = ex f(0) = 1 = Yo f(1) = 2.72 = yı f(2) = 7.39 у2 = f(3) 20.09 у3 = = f(4) = 54.60 у4 = Here h = 1. Applying Simpson's rule, we get Int_{f(x)}dx h 3 = [yo+2[y2] + 4[y1 + yз] + y4] 1 3 = [1+2(7.39)+4(2.72 + 20.09) + 54.60] = [161 [161.62] = 53.8733

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