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Deepikachaudhary posted an Question
June 06, 2021 • 16:30 pm 30 points
  • CSIR NET
  • Mathematical Sciences

4. counting of odd days: 1.1 ordinary year = 365 days = (52 weeks+1 day) 1 ordinary year has 1 bdd day. 2.1 leap year = 366 days = (52 weeks + 2 days) 1 leap ye

4. Counting of Odd Days: 1.1 ordinary year = 365 days = (52 weeks+1 day) 1 ordinary year has 1 bdd day. 2.1 leap year = 366 days = (52 weeks + 2 days) 1 leap year has 2 odd days. 3. 100 years 76 ordinary years + 24 leap years = (76 x 1+ 24 x 2) odd days = 124 odd days = (17 weeks+ days)= 5 odd days. Number of odd days in 100 years = 5. Number of odd days in 200 years = (5 x 2) = 3 odd days. Number of odd days in 300 years = (5 x 3) 1 odd day Number of odd days in 400 years (5 x 4+ 1) = 0 odd day Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days.

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  • Alka gupta

    provided solution is absolutely correct...see

    cropped7012135218659167166.jpg
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    my question is why we write here 124 odd days = 17 weeks + days ???and = 5 odd days

    eduncle-logo-app

    odd days not greater than 7...it is always 0 to 6 ....if we get 7 or more than 7 odd days then it will converts into a week

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