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Deepikachaudhary Asked a Question
June 6, 2021 11:00 ampts 30 pts
4. Counting of Odd Days: 1.1 ordinary year = 365 days = (52 weeks+1 day) 1 ordinary year has 1 bdd day. 2.1 leap year = 366 days = (52 weeks + 2 days) 1 leap year has 2 odd days. 3. 100 years 76 ordinary years + 24 leap years = (76 x 1+ 24 x 2) odd days = 124 odd days = (17 weeks+ days)= 5 odd days. Number of odd days in 100 years = 5. Number of odd days in 200 years = (5 x 2) = 3 odd days. Number of odd days in 300 years = (5 x 3) 1 odd day Number of odd days in 400 years (5 x 4+ 1) = 0 odd day Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days.
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  • Avijeet banerjee thankyou
    124=17×7+5 =17 weeks+ 5 days.
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  • Alka gupta
    provided solution is absolutely correct...see
    • cropped7012135218659167166.jpg
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    Deepikachaudhary
    my question is why we write here 124 odd days = 17 weeks + days ???and = 5 odd days
  • Deepikachaudhary
    y kya kiya yaha pr ???
    • cropped1092010678993061071.jpg
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