2m.C) cannot take place because it violates the conservation of (A) Charge (B) Parity (C) Charge conjugation (D) Lepton number"> 2m.c) cannot take place because it violates the">
Sharanya posted an Question
April 09, 2021 • 00:56 am 30 points
  • CSIR NET
  • Physical Sciences

74. the reaction ->0+e" (for e, > 2m.c) cannot take place because it violates the conservation of (a) charge (b) parity (c) charge conjugation (d) lepton number

74. The reaction ->0+e" (for E, > 2m.C) cannot take place because it violates the conservation of (A) Charge (B) Parity (C) Charge conjugation (D) Lepton number

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  • Devisharan best-answer

    Answer Charge is conserved in given reaction since -1+1=0 both sides. Lepton no. is conserved since L=-1 for electron and L=-1 for Positron. also charge conjugation is conserved since all charge reversed in charge conjugation. Now rest is Parity. So Parity is not conserved in given reaction.

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