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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Debanjana Adhikari posted an Question
May 25, 2020 • 00:40 am
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30 points
30 points
- CSIR NET
- Physical Sciences
A uniform solid cylinder is released on a horizontal surface with speed 5m/s without any rotation (slipping without rolling). the cylinder eventually starts rol
A uniform solid cylinder is released on a horizontal surface with speed 5m/s without any rotation (slipping without rolling). The cylinder eventually starts rolling without slipping. If the mass and radius of the cylinder are 10 gm and lcm respectively, the final linear velocity of the cylinder is... ....... m/S. (up to two decimal places). 3.33
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Ruby negi
total angular momentum of cylinder is linear momentum plus rotational momentum ( rotational momentum because cylinder is rolling). now linear momentum is m*(Vcm)*r and rotation angular momentum is I*omega (omega is angular frequency and I is moment of inertia i.e I=mr^2/2). and one more thing omega=(Vcm)/r. put these values you will get your ans(Vcm=2/3V in the ans).. you can go through the solution of Ms. vaishali..for any doubt we are here...best regards...
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Chandra prakash
see attached file it's very helpful for you dear
I hope you got it my point dear
L = M + I W