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Eduncle posted an MCQ
October 20, 2019 • 16:48 pm 0 points
  • CSIR NET
  • Life Sciences

Assuming that the A, B, C and D genes are not linked, the probability of a progeny being AaBBccDd from a cross between AaBBccDd and aaBBccDD parents will be

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    Eduncle Best Answer

    GENOTYPE OF PARENTS – AABbccDd X aaBBccDD
    Gametes from parent 1 – A             parent 2 – a
                                  B or b                 B
                                  c                         c
                                  D or d                 D
    Genotype for individual gene pairs in progeny – Aa
                                                              BB/ Bb
                                                              cc
                                                              DD/Dd
    Probability of (AaBBccDd) Genotype of progeny - 1 × 1/2 × 1 × 1/2 = 1/4 (As genes are not linked individually, probability as multiplied by product rule of probability for independent events)

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