CSIR NET Follow
Nivedha Asked a Question
January 15, 2021 10:04 pm 30 pts
At a given temperature, for a rigid rotor, the probability that the system is in the rotational state J =0 is 0.6, in state J =1 is 0.3 and 0.1 in J = 2. The energy in a rotational state, J is given by J(+1)B, where B is the rotational constant. The average energy ofthe rotor at the given temperature is (a)-6.0B (b) 1.2 B (c) 3.6B (d) 4.8 B