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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Bidyut sinha Best Answer
1) For Normal Zeeman effect ,spin value(S=0) and for Anomalous Zeeman effect spin value Should NOT be equal to 0(S NOT equal to 0) 2.Now in this case for first case 1F3 to 1D2, Spin value is determined such as; 2s+1=1, so s=0...So first case is "Normal" Zeeman effect 3.For the second case 2D3/2 to 2P1/2, spin value is determined such as; 2s+1=2,or s=1/2 ,Not equal to Zero. So it is " Anomalous Zeeman effect". (a)Normal, Anomalous
thanku so much..understood very well
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