Sarbeswarmahalik Asked a Question
December 12, 2019 2:48 pmpts 25 pts
C6 istry Ihe high spin d* complex Cr (H,O).is labile but the low spin d' complex ion Cr(CN). is inert. The Correct explanation is ) Cr(H,O), one unpaired electron is present in an anti-bonding which makes substitution relatively G)In Cr (CN), one electron is present in the anti-bonding orbital which makes the substitution relatively i) In Cr(CN), to transfer the electron in the anti-bonding "eg" orbital required high energy due to (iv) The strong T-bonding with CN also strengthens the Cr-C bonds in the Cr(CN) (a) ionly easy. slow which the reactions become slow. (c)i ii (d) i,ii, iv (b) ii only
  • 0 Answer(s)
  • 0 Likes
  • 1 Comments
  • Shares
  • Suresh khokhar thankyou
    Ans is d
    • upload_1576166334090.jpg
    • upload_1576166357424.jpg
    Likes(0) Reply(0)
Head Office :
MPA 44, 2nd floor, Rangbari Main Road,
Mahaveer Nagar II, Kota (Raj.) – 324005

Corporate Office:
212, F-1, 2nd Floor, Evershine Tower,
Amrapali Marg,
Vaishali Nagar, Jaipur (Raj.) – 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com