Sarbeswarmahalik Asked a Question
December 12, 2019 2:48 pmpts 25 pts
C6 istry Ihe high spin d* complex Cr (H,O).is labile but the low spin d' complex ion Cr(CN). is inert. The Correct explanation is ) Cr(H,O), one unpaired electron is present in an anti-bonding which makes substitution relatively G)In Cr (CN), one electron is present in the anti-bonding orbital which makes the substitution relatively i) In Cr(CN), to transfer the electron in the anti-bonding "eg" orbital required high energy due to (iv) The strong T-bonding with CN also strengthens the Cr-C bonds in the Cr(CN) (a) ionly easy. slow which the reactions become slow. (c)i ii (d) i,ii, iv (b) ii only
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  • Suresh khokhar thankyou
    Ans is d
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