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Ex. find the vector whose magnitude is 15 and which is perpendicular to ( k) and lies in the plane pm 2x3y z = 15. then the gradient of d is perpendicular to th
Ex. Find the vector whose magnitude is 15 and which is perpendicular to ( k) and lies in the plane pm 2x3y z = 15. Then the gradient of d is perpendicular to the surface = constant. L.e. is perpendicular to the required vector which is also perpendicular to the vector (i+K). Thus we have a vector along the required vector such that Sol. Let 2x 3y+Z 15 constant. grad-V(2x+3y+2)=2i+3]+k A- )xgrad - kx(2i 3 k)
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Dhairya sharma
dear dkho ek vector to diya hua h que m....uske or grad phi k perpendicular nikalna h to cross product krna h.
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Ruby negi
my approach is the required vector is perpendicular to j+k vector so the dot product of required vector(V) and j+k is zero. and also the V vector is on the plane 2x+3y+z so the grad of plane(that is perpendicular to plane and also V vector as V vector is on the plane) is also perpendicular to V so the dot product of V and grad of plane is also zero. from these two you will get the coefficients of vector...