Dhruv Verma Asked a Question
May 30, 2020 3:45 pmpts 30 pts
Ex. Find the vector whose magnitude is 15 and which is perpendicular to ( k) and lies in the plane pm 2x3y z = 15. Then the gradient of d is perpendicular to the surface = constant. L.e. is perpendicular to the required vector which is also perpendicular to the vector (i+K). Thus we have a vector along the required vector such that Sol. Let 2x 3y+Z 15 constant. grad-V(2x+3y+2)=2i+3]+k A- )xgrad - kx(2i 3 k)
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  • Ruby negi
    my approach is the required vector is perpendicular to j+k vector so the dot product of required vector(V) and j+k is zero. and also the V vector is on the plane 2x+3y+z so the gra...
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  • Ruby negi
    • cropped-1936253033.jpg
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  • Dhairya sharma
    dear dkho ek vector to diya hua h que m....uske or grad phi k perpendicular nikalna h to cross product krna h.
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  • Dhruv Verma
    Ok but isme A vector ko solve kaise kiya hai kya aap wo explain kar sakti hai
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    Ruby negi
    A vector is not a required vector,it is just a vector along our required vector..
  • Dhairya sharma thankyou
    dear must remember that gradiant is perpendicular to the surface.
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    Dhairya sharma
    and if we want perpenducular to that we need cross product