Narasimman posted an Question
September 14, 2021 • 21:54 pm 30 points
  • CSIR NET
  • Chemical Sciences

Example 5: find the value of v80 +3/245-v125. solution: s0= v16x5 = 4v5 3245 3v49x5 = 215 v125 = 25 x5 = 5v5 :. 80 +3v245-125 - 45 +215-5v5 = 20/5

Example 5: Find the value of V80 +3/245-V125. Solution: s0= V16x5 = 4V5 3245 3V49x5 = 215 V125 = 25 x5 = 5V5 :. 80 +3V245-125 - 45 +215-5V5 = 20/5

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