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Bhavana Garg A posted an Question

January 29, 2022 • 17:36 pm 30 points

Explain all 3 14,15,16

ncle g and Aptituda Mathematical Reasoning and Aptitude Km/hr in the direetion opposite to Wha iuat is the time taken by a train of (A) 40 m travelling at 90 km/hr to cross an athlete running at 36 36 sec to the train ? (C) 42 sec 24 scC (B) Re elative speed SCC (B) 20 (D) Distance to be crossed 90 +36 126 km/hr 12.5m/s. m (length of the biker can be neglected as if negligible when compared at the rate to that of the train). end of Time40 24 sec 35 A br bus started its journey vely h. If the average speed of bus OCC and reached Saharanpur in 44 minute with its average speed du K distance ? Ous is increased by 5 km/h. How much time will it take to coVer ui (A) 31 min (B) 36 min 40 min (C) 38 min (D) (D) and 44 Distance = x 50 60 OW as the spced is increased by 5 km/h, new speed w1ll be 50+5= 55 km/h T ime taken when speed is increased by 44 x 50 5 km/h = 60 55 = 2/3 hour = 40 min. meter behind. If the speed of the ambulance is 30 km/h, what is the speed of the college bus ? (B) l6 1he driver of an ambulance sees a college bus 40 m ahead of him after 20 seconds, the college bus is 60 12 kmph (A) 10 kmph 22 kmph (D) (C) 15 kmph (B) Relative Speed = (speed of ambulance - speed of college bus) Relative Distance of 60 + 40 100 metres is covered in 20 second. So Relative speed is 100/20 5m/s Covert this into Km/h by multiplying with 18/5 Relative Speed in Km/h 18 Km/h Speed of College bus = Speed of ambulance - relative speed. lr

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