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Arjun Singh posted an Question
July 19, 2020 • 00:47 am 50 points
  • UGC NET
  • Computer Science & Applications

Explain this question properly

explain this question in detail how it's been solved

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    Nabeela Best Answer

    first read this image...if a schedule is not CS and you find a blind write like in this question, it is not CS as there is a cycle between t1 and t2 and there is also a blind write t3, then we'll check 3 conditions considering serial schedule t1:t2:t3:t4 1. initial read should be same for each variable 2. if tj reads a variable written by ti in some concurrent schedule, that must satisfy in the corresponding serial schedule as well. 3. final write for each variable must be same in both schedules. so according to these conditions, this schedule is view serializable.

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