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Sureeti posted an Question
May 15, 2021 • 00:43 am 30 points
  • UGC NET
  • General Paper 1

Graicunas theory of span control

graicunas theory of span control can you explain this in detail with proper explaination ,also does it comes in exam to calculate or what type of questions are asked for this

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  • Rucha rajesh shingvekar best-answer

    Graicunas, introduced a theory on span of management which explains three kinds of relationships that a superior can have with subordinates. He formulated a theory and suggested the number of subordinates under one superior based on mathematical calculations. As per me you will be ask questions on given chart.

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    Vikas Gupta Best Answer

    This theory is all about superior and subordinate relationship. this is not a empirical observation. but based on mathematical formula. This formula written by V.A Graicunas a French management consultant. Graicemas has identified three specific kinds of superior and subordinate relationships in every organisation. 1. Direct Single Relationship: we will understand with example like if A has three subordinates, there would be three direct single relationships. this has been identified as Number of direct relationships=N 2. Direct Group Relationships:This means the group relationships between the superior and each possible combination of subordinates. A manager has occasions to consult, confer, advise, inform or discuss with every subordinate or any number of them or all of them in attendance. This means relationship arises between the superior and his group of subordinates. Example: A manager having three subordinates would have three direct group relationships. Formula = n (2n-1 -1) where n represents the number of subordinates. 3. Cross Relationship:Cross relationships are mutual relationships among subordinates necessary for working under the same superior. This result from the need of the subordinates of a common superior to consult with one another. Resulting from the above analysis of the three kinds of relationships, Graicunas developed the following formula to give the total number of all the three kinds of relationships where n = number of subordinates. n(2n/2 + n + 1)

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    Hi I want to discuss in detail your answer is good but want more explanation and practical way

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