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Nisha Sharma posted an Question
March 20, 2021 • 21:31 pm
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- UGC NET
- Commerce
His ous km/hr, he before the use from (5) none of above 4 hours a walks at speed 4 km/hr. after 4 hours d 10 km/hr. after b starts cycling at speed 10 km/hr. af
his ous km/hr, he before the use from (5) None of above 4 hours A walks at speed 4 km/hr. After 4 hours d 10 km/hr. After B starts cycling at speed 10 km/hr. After atch up with how much distance will B catch up with A? A 2001] (1) 16.7 km (2) 18.6 km (4) 26.7 km (3) 21.5 km Nane of above [Income Tar 1993 reaches
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Priya gulani
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Speed of A = 4km/h Speed of B = 10km/h Due to delay of 4 hours , A is 16 Km far from B. And They move in same direction then Relative speed is 6km/h Then Time is 16/6 which is 8/3 Then we find distance from B so Distance =speed × time Distance =8/3 ×10=26.7 km
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Rucha rajesh shingvekar
formula for relative speed in same direction is ( speed of B - Speed of A) So relative speed =10-4=6km/hr Total distance between A and B is(4*4)=16km Time =Distance /Speed =16/6 =8/3 therefore Distance = speed * time = 10* 8/3 =26.7km