Nisha sharma Asked a Question
March 20, 2021 4:01 pmpts 30 pts
his ous km/hr, he before the use from (5) None of above 4 hours A walks at speed 4 km/hr. After 4 hours d 10 km/hr. After B starts cycling at speed 10 km/hr. After atch up with how much distance will B catch up with A? A 2001] (1) 16.7 km (2) 18.6 km (4) 26.7 km (3) 21.5 km Nane of above [Income Tar 1993 reaches
  • 1 Answer(s)
  • 0 Likes
  • 2 Comments
  • Shares
  • Rucha rajesh shingvekar
    formula for relative speed in same direction is ( speed of B - Speed of A) So relative speed =10-4=6km/hr Total distance between A and B is(4*4)=16km Time =Distance /Speed ...
    Show more
    • cropped5855109059758670782.jpg
    Likes(0) Reply(0)
  • Priya gulani thankyou
    Speed of A = 4km/h Speed of B = 10km/h Due to delay of 4 hours , A is 16 Km far from B. And They move in same direction then Relative speed is 6km/h Then Time is 16/6 which is ...
    Show more
    Likes(0) Reply(0)
Head Office :
MPA 44, 2nd floor, Rangbari Main Road,
Mahaveer Nagar II, Kota (Raj.) – 324005

Corporate Office:
212, F-1, 2nd Floor, Evershine Tower,
Amrapali Marg,
Vaishali Nagar, Jaipur (Raj.) – 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com