30 points
>
Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- CSIR NET
- Life Sciences
How it can be 60% ?
1 Answer(s)
Answer Now
- 1 Likes
- 2 Comments
- 0 Shares
-
![comment-profile-img]()
>
Narayan singh Best Answer
The production of ATP by oxidative phosphorylation is approximately 60% that's right because in in the complete oxidation of glucose into CO2 is complete in three basic steps that is glycolysis krebs cycle and electron transport chain. in the glycolysis only 2 ATP produced but 2 NADH also produced and in the Krebs cycle 2 ATM , 6 NADH & 2- FADH2 produced. now NADH and FADH2 participate in electron transport chain or oxidative phosphorylation and form electro-chemical-proton gradient which ultimately form proton motive force. this proton motive force responsible for proton movement through ATP synthase in the mitochondria and ATP are form by ATP SYNTHASE. 1 NADH form 2.5 ATP & 1 FADH2 FORM 1.5 ATP through oxidative phosphorylation so we can count 10 NADH form in complete oxidation of glucose in 6 CO2 THEN 25 ATP are form. and 2 FADH2 also form in this process so it form 3 ATP. In the overall glycolysis 28 ATP form by oxidative phosphorylation through election transport chain and 4 ATP form by substrate level phosphorylation
![cropped4907134120894587404.jpg]()
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Aditi
okay... thank uh.