Vaishnavi posted an Question
March 12, 2021 • 01:26 am 15 points
  • UGC NET
  • Computer Science & Applications

If u=sin^-1(x+2y+3z)/(x^8 +y^8+z^8) then find the value of xux+yuy+zuz

if u=sin^-1(x+2y+3z)/(x^8 +y^8+z^8) then find the value of xUx+yUy+zUz

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    Suganya jagath best-answer

    Given, sinu=x8+y8+z8​x+2y+3z​ Differentiating on both sides, we get, cosu∂x∂u​=∂x∂​(x8+y8+z8​x+2y+3z​) ⇒∂x∂u​=sinutanu​∂x∂​(x8+y8+z8​x+2y+3z​) ⇒∑x∂x∂u​=x+2y+3zx8+y8+z8​​tanu((x8+y8+z8)x8+y8+z8​(x8+y8+z8)(1x+2y+3z)−(x+2y+3z)(4x7x+4y7y+4z7z)​) ⇒∑x∂x∂u​=tanu(1−4) ⇒∑x∂x∂u​=−3tanu hope you understand

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