Vaishnavi Asked a Question
March 11, 2021 7:56 pmpts 15 pts
if u=sin^-1(x+2y+3z)/(x^8 +y^8+z^8) then find the value of xUx+yUy+zUz
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  • Suganya jagath thankyou
    Given, sinu=x8+y8+z8​x+2y+3z​ Differentiating on both sides, we get, cosu∂x∂u​=∂x∂​(x8+y8+z8​x+2y+3z​) ⇒∂x∂u​=sinutanu​∂x∂​(x8+y8+z8​x+2y+3z​) ⇒∑x∂x∂u​=x+2y+3zx8+y8+z8​​tanu((x...
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  • Priyanka meher
    −3 tan u
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