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Eduncle posted an MCQ
October 19, 2019 • 22:39 pm 0 points
  • CSIR NET
  • Life Sciences

In Burkitt's Lymphoma a reciprocal translocation between chromosome 8 and 14 is observed. If an individual is heterozygous for this translocation, the

In Burkitt's Lymphoma a reciprocal translocation between chromosome 8 and 14 is observed. If an individual is heterozygous for this translocation, the consequence in meiosis will be as follows: (a) Four chromosomes, i.e., normal chromosome 8 and 14, and translocated chromosome 8 and 14, pair together (b) The two normal chromosomes 8 and 14, and two translocated chromosomes pair separately (c) All gametes produced from this meiosis are non-viable as they have deletions and duplications (d) In one of the cross configuration called "alternate segregation" all gametes having normal or translocated chromosomes, survive (e) The gametes having normal chromosomes only survive while and gametes having translocated chromosomes are non-viable, hence the translocations are used as crossover suppressors Which of the following combinations best describes the meiotic consequences for the translocation described above ?

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    Eduncle Best Answer

    In Burkitt lymphoma cells reciprocal chromosomal translocations are observed between the long arm of chromosome 8  and either the long arm of chromosome 14 , the short arm of chromosome 2  or the long arm of chromosome 22.
    One set of normal chromosomes and one set of translocated chromosomes are involved, the result is a cross like configuration in meiotic prophase I.
    In alternate segregation, alternate centromeres migrate to the same pole. This produces two gametes, each of which is viable because it contains a complete set of genes—no more, no less. One of these gametes has two normal chromosomes, and the other has two translocated chromosomes.

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