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Debanjana Adhikari posted an Question
May 24, 2020 • 14:13 pm 30 points
  • CSIR NET
  • Physical Sciences

Institute for net/jre, gate, it-jam, jest, tifr and gre in physical scieng the number of degrees of freedom of a rigid body in d space-dimensions is (a) 2d (b)

Institute for NET/JRE, GATE, IT-JAM, JEST, TIFR and GRE in PHYSICAL SCIENG The number of degrees of freedom of a rigid body in d space-dimensions is (a) 2d (b) 6 () dld +1/2 (d) d!

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    Abhishek singh best-answer

    This will definately give you intuitively knowledge. I have shown for 1,2,3-dimensional space. Then I generalised. This will surely help you to build the concept. Now you can remember the formula. warm regards.

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    you can ask doubts if any

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    for 3-dimension. You are free to rotate the body in all directions and you can also translate it in all directions.

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    Chandra prakash Best Answer

    see attached file... it's very helpful for you dear

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    if you any doubt regarding this.. u can ask

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    Ruby negi best-answer

    this is the direct formula.. d(d+1)/2 for rigid body...

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    remember this formula

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    this is in d-space.. if it in 3-d space then d.o.f is 3(3+1)/2 i.e 6

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