profile-img
Debanjana adhikari Asked a Question
May 24, 2020 8:43 ampts 30 pts
Institute for NET/JRE, GATE, IT-JAM, JEST, TIFR and GRE in PHYSICAL SCIENG The number of degrees of freedom of a rigid body in d space-dimensions is (a) 2d (b) 6 () dld +1/2 (d) d!
  • 3 Answer(s)
  • 0 Likes
  • 5 Comments
  • Shares
  • Chandra dhawan
    Dof = d(d+1)/2
    Likes(0) Reply(0)
  • Abhishek singh thankyou
    This will definately give you intuitively knowledge. I have shown for 1,2,3-dimensional space. Then I generalised. This will surely help you to build the concept. Now you can remem...
    Show more
    • cropped4174215756809173271.jpg
    Likes(1) Reply(2)
    Abhishek singh
    you can ask doubts if any
  • Chandra dhawan Best Answer
    see attached file... it's very helpful for you dear
    • cropped-234366709.jpg
    Likes(1) Reply(1)
    Chandra dhawan
    if you any doubt regarding this.. u can ask
  • Dhairya sharma
    dear it's fixed formula.
    • cropped3660536369485106585.jpg
    Likes(0) Reply(0)
  • Ruby negi thankyou
    this is the direct formula.. d(d+1)/2 for rigid body...
    Likes(2) Reply(2)
    Ruby negi
    remember this formula
Head Office :
MPA 44, 2nd floor, Rangbari Main Road,
Mahaveer Nagar II, Kota (Raj.) – 324005

Corporate Office:
212, F-1, 2nd Floor, Evershine Tower,
Amrapali Marg,
Vaishali Nagar, Jaipur (Raj.) – 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com