Debanjana adhikari Asked a Question
May 24, 2020 8:43 ampts 30 pts
Institute for NET/JRE, GATE, IT-JAM, JEST, TIFR and GRE in PHYSICAL SCIENG The number of degrees of freedom of a rigid body in d space-dimensions is (a) 2d (b) 6 () dld +1/2 (d) d!
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  • Chandra dhawan
    Dof = d(d+1)/2
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  • Abhishek singh thankyou
    This will definately give you intuitively knowledge. I have shown for 1,2,3-dimensional space. Then I generalised. This will surely help you to build the concept. Now you can remem...
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    Abhishek singh
    you can ask doubts if any
  • Chandra dhawan Best Answer
    see attached file... it's very helpful for you dear
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    Chandra dhawan
    if you any doubt regarding this.. u can ask
  • Dhairya sharma
    dear it's fixed formula.
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  • Ruby negi thankyou
    this is the direct formula.. d(d+1)/2 for rigid body...
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    Ruby negi
    remember this formula