Jenifa begum Asked a Question
March 8, 2021 7:58 ampts 51 pts
is a pc parucle of mass m then force between these particles is not given by adove TOmula M xdmple: As shown in fiqure if one of the object is block of mass M and anotherin m d GMm i.e. F because density is not uniform lo solve this we have to use integration as follows nt is dx (He irst take a mass element dM at distancex from one side of rod and length of element is d. length of rod is ). ll2- dM x = 0 m X =l dx d (d- x+02) Force due to element taken Gm dM dF (d-x+0/2) Gm dM F=J(d-x+012 We have to convert dM in terms of dx llength has mass M dx length has mass dx unitary method (use only for uniform object) dx Substituting dM-dx Therefore, Gravitational force between both particles is Gm(M/e)dx F= Jo (d- x+ ll2) GmM F -1 1 (d-x+ll2)J, (-1) GmM GmM F ld-(e12 d-214 GmM F 214 tact Us eheit
  • 1 Answer(s)
  • 0 Likes
  • 1 Comments
  • Shares
  • Dinesh vishwakarma thankyou
    block mass, M is a Rigid body. So it has continuous mass distribution. That's why we need to do integration on taking a small mass slice and put the limit for hole body. If ma...
    Show more
    Likes(0) Reply(0)
Head Office :
MPA 44, 2nd floor, Rangbari Main Road,
Mahaveer Nagar II, Kota (Raj.) – 324005

Corporate Office:
212, F-1, 2nd Floor, Evershine Tower,
Amrapali Marg,
Vaishali Nagar, Jaipur (Raj.) – 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com