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Debanjana Adhikari posted an Question
May 25, 2020 • 18:22 pm 30 points
  • CSIR NET
  • Physical Sciences

Kxe=weh; kxh=-wue how??

For a plane wave of angular frequency o and propagation vector k propagating in the medium Maxwell's equations reduce to (a) k E =0; k H = 0; kxE=øsh; kxH=-ouE (b) k E=0; k H =0; kxE= -os H; kx H =ouE (c) kE =0; k.H =0; kxE= -ouH; k xH=osE (d) k E=0; k.H =0; kxE =ouH; kxH=-wEE

3 Answer(s) Answer Now
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  • comment-profile-img>
    Abhishek singh

    I have derived each step.This will surely help you.

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    option D is correct

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    you can simply see from diagram for first two parts

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    you can ask doubts if any.

  • comment-profile-img>
    Chandra prakash best-answer

    see attached file it's very helpful for you dear.....

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    I hope you will get it dear

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    if you want some clarification.. u can ask..

  • comment-profile-img>
    Ruby negi Best Answer

    k is the direction of propagation and you know direction of propagation is always perpendicular to e.f and m.f. ... also H=B/permeability so option a is correct...

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    option a is correct.

  • comment-profile-img>
    Dhairya sharma

    dear see attached.

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    here i used the concept the em wave in which del is representted as ik and d/dt as -iw.

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    i hope dear this will help you.

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    for further clarifications plz ask.

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