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Anonymous User Best Answer
f(x)=ax³+bx²+CX+d a+b+c+d=3 27a+9b+3c+d=7 125a+25b+5c+d=11 Limit x²(ax³+bx²+CX+d)/(2x⁵+3)=6 So a=12 f(0)=d=-179