Pooja Banwari posted an Question
February 12, 2021 • 16:03 pm 30 points
  • CSIR NET
  • Mathematical Sciences

Pl = (d-1) d-2d+2) d-3d+ 4d- 1 e + 1 1 9+ (d-1(1-2+2)(-1)d -3(-1) + 4d-2 1 1 e+ 3d+ +1 cos x = (d-1) 3d-1 1+ = e d+1-1 9d2-1 cos x = e1+ 1 (-3 sinx-cos x) -9-1

Pl = (D-1) D-2D+2) D-3D+ 4D- 1 e + 1 1 9+ (D-1(1-2+2)(-1)D -3(-1) + 4D-2 1 1 e+ 3D+ +1 COS X = (D-1) 3D-1 1+ = e D+1-1 9D2-1 COS X = e1+ 1 (-3 sinx-cos x) -9-1 1 = ex + (3 sin x + Cos x) complete solution is +

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    Satpal singh

    if you have any doubt then you ask. if you are satiafied with this accept this as best answer

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