Jayasree Asked a Question
February 20, 2022 11:16 ampts 20 pts
Q54. A uniform volume charge density is placed inside a conductor (with resistivity10 Qm). 1 of its original value after time.....Fermi seconds The charge density becomes (2.718) (up to two decimal places) (6=8.854x10 F/m) Ans.: 88.54
  • 1 Answer(s)
  • Shares
  • Subhra sankha das thankyou
    From continuity equation of charge, find ln(2.718) equals to time by epsilon not. Then you get the value of t in terms of fermi seconds
    Likes(0) Reply(0)