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Deepikachaudhary Asked a Question
August 14, 2020 12:17 pmpts 30 pts
r and 0 are called polar 3+2isin0 S Va finition Find real 0 such tnat 1-2isin 0 Example --9 Purely Real and Purely Imaginary Kosovalzed, i () Solution: 3+2isin (3+2isin 0)(1+ 2isin 0) 1+ 4sin0 Let Z 12isin 3-4 sin +i Z 1+4 sin 0 8 sin0 1+4 sin0 Z z is purely real Im(z) = 0 if polm sin 0 0 Qnd hU 0 nT see ke ka i) z is purely imaginary Re (z) = 0 ally re sin 0 = sin 0 =/nr 3
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  • Satpal singh Best Answer
    see the attachment
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  • Deepak singh thankyou
    see attached
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  • Deepak singh
    it's formula
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