Chashokreddy18@gmail.com Tiwari Asked a Question
June 23, 2020 11:03 ampts 30 pts
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  • Chashokreddy18@gmail.com Tiwari
    I have attached two images, please see that. My doubt is when I solved by using the def of differentiability , I got discontinuous everywhere. So I request once you to check and so...
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  • Chashokreddy18@gmail.com Tiwari
    But even at other points like x= 2 and so on, the LEFT HAND and RIGHT HAND DERIVATIVES are not equal.
    • cropped1761938464.jpg
    • cropped838669506.jpg
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  • Chashokreddy18@gmail.com Tiwari
    At x = 1, -1 LEFT HAND and RIGHT HAND DERIVATIVES are not equal ,so discontinuous.
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  • Chashokreddy18@gmail.com Tiwari
    can you please explain from this image ( by using the formula of differentiability).
    • cropped-1279807529.jpg
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  • Priyadarshan Choursiya thankyou
    see attachment
    • cropped7539090548306067566.jpg
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    Chashokreddy18@gmail.com Tiwari
    can you please explain?