pg 768 I think the solution has some mistakes volume 2

So, x = and x= are positions where dF0 3 1A) dx Therefore = 2 X Jx/wP dx xf (x) dx J dx C1a) 3 - Now, f(x) dx xexp dx xassume only positive values = x exp x dx 2b 1 2 2 22 Ratio x2 i.e.