Solve xy + 2xy-2xy 20y (x+ 1) ex. sol. by 0 method, we get [e(e 1) + 20 20]y = (x +1)p [e+0 20]y = (x+ 1) (5)(0- 4)y (x + 1) cf c,xx +cx 1 pl and (+0-20)x+1) 1

Solve xy + 2xy-2xy 20y (x+ 1) Ex. Sol. By 0 method, we get [e(e 1) + 20 20]y = (x +1)P [e+0 20]y = (x+ 1) (5)(0- 4)y (x + 1) CF C,Xx +CX 1 Pl and (+0-20)X+1) 1 (x*+2x+1) (0+0-20) 1 (using Rule Il) +2-20*+21+1-20*201 1420 or, we may use an alternative method Pl (0+0-201X+ 1)2 1 1 (x +1) (0+5)(0-4) 1 (Rule I) (0+5 X°(x + 1) dx Hence, Pl- 20 2x 1 y=c,x+Cx- 20 is the required solution.