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Vijay posted an Question
June 25, 2022 • 02:07 am 30 points
  • CSIR NET
  • Mathematical Sciences

The dimension of the vector space of all symmetric matrices of order nxn with real entries and trace equal to zero is t(+1) 2 (2) +1 () 2 nn +1+1 (4) 2

The dimension of the vector space of all symmetric matrices of order nxn with real entries and trace equal to zero is T(+1) 2 (2) +1 () 2 nn +1+1 (4) 2

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  • Anonymous User Best Answer

    a11+a22+...+ann=0 a11=-(a22+a33+...ann) so dim 1 less but dim of symmetry matrix is n(n+1)/2 so options A

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