Nivedha posted an Question
January 21, 2021 • 18:04 pm 30 points
  • CSIR NET
  • Chemical Sciences

The equilibrium population ratio (n, / n) of a doubly-degenerate energy level (e) lying at energy 2 units higher than a lower non-degenerate energy level (e), a

The equilibrium population ratio (n, / n) of a doubly-degenerate energy level (E) lying at energy 2 units higher than a lower non-degenerate energy level (E), assuming kT =I unit, will be (a) 2e2 (b) 2e2 (c) e (d) e-2

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    Lingareddy 1 Best Answer

    option A n2/n1= g2/g1×e^(-E/kT) n2/n1=2×e^(-2/1) n2/n1=2×e^(-2)

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