Nivedha posted an Question
January 27, 2021 • 15:46 pm 30 points
  • CSIR NET
  • Chemical Sciences

The major product obtained in the following reaction: ch h hc i) mel is ph i) ag,o, h,0 h nme2 (ii) a hc ph (c) ph ch2 ch3 hc ch3 h3c h ch2 (a) ph (b) ph (d) hc

The Major Product obtained in the following reaction: CH H HC i) Mel is Ph i) Ag,O, H,0 H NMe2 (ii) A HC Ph (c) Ph CH2 CH3 HC CH3 H3C H CH2 (a) Ph (b) Ph (d) HC H H H H H

3 Answer(s) Answer Now
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    Priyanshu kumar best-answer

    option C is correct...It is exhaustive methylation and hoffmann product favours

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  • comment-profile-img>
    Dinesh khalmaniya 1 Best Answer

    option C Explanation- The first step is to treat an amine with a vast excess of methyl iodide [CH3I], which results in an ammonium salt [we saw this reaction, “exhaustive methylation”, The second step is to distill the ammonium salt under low pressure in the presence of a strong base. Silver oxide (Ag2O) is often used. The interesting observation here is that the alkene product from this process tends to be the least substituted alkene (“Hofmann product”) not the Zaitsev product. The Hofmann Elimination Has An Extremely Bulky Leaving Group, And This Leads To “Non-Zaitsev” Elimination Products

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    got it Nivedha?

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    sir, i understand this. but the answer given was option B. Isn't this supposed to be Anti-elimination? In that case, is option B the right one? I don't understand if we should see Hoffman's pdt or Anti- elimination.

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