Akash Babu posted an Question
July 30, 2022 • 10:52 am 30 points
  • CSIR NET
  • Mathematical Sciences

Then, 37. let f2)= xp z (a) f has an isolated singularity at z = 0 (c) f has infinitely many poles (5) i has a removable singularity at z (d) each pole of f is

then, 37. Let f2)= xp Z (A) f has an isolated singularity at z = 0 (C) f has infinitely many poles (5) I has a removable singularity at z (D) Each pole of f is of order 1

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  • Anonymous User best-answer

    the pole of f(z) is give by exp(2pii/z)=1 z=1 which is a simple pole

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