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Meghna Khadka posted an Question
September 04, 2020 • 12:36 pm 30 points
  • CSIR NET
  • Chemical Sciences

Why on ionization electrons are removed from 4s orbitals are removwd first than 3d orbital in case of transition metals?

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    Priyanshu kumar best-answer

    Dear student, Filling of orbitals takes place by considering aufbau rule(n+l) ...The orbitals whose n+l value is smaller filled first.... Between 4s and 3d ...4s has n+l value=4+0=4 and 3d has n+l value=3+2=5...so 4s orbital is filled according to aufbau rule...... Now come to the situation of ionisation as for greater value of principal quantum number 'n' the outermost orbital is decided as it has maximum distance from nucleus and influence of nucleus or we can say nuclear charge is less effectively pronounced for outermost orbital...So 4s is outermost orbital here..So removal of electrons takes place firstly from 4s orbital then 3d orbital...

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    Means fillings of orbitals and removal of electrons are working for 4s and 3d in opposite manner...

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    Hope this will helps your queries...

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    Dinesh khalmaniya 1

    As 4s orbitals have a lower energy than 3d orbitals, electrons are first filled in the 4s orbital and then in the 3d orbital. ... This is because the outer shell is maximum shielded from the influence of the nucleus, and hence lower energy is required to extract electrons from the outermost shell than from an inner shell.

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    Dinesh khalmaniya 1

    because 4s is outer most shell so attraction with nucleus less than 3d

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    any doubt?

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    yes, actually when filling up of electrons 4s is filled up first than 3d then how come 4s is outermost shell ? any reason

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    because principal quantum number 4 for 4S is greater than 3 for 3d

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    highest the value of n , outer most will be the shell

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    but electrons filled out according to n+l rule,

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    check it

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    ok thank you

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    please accept the answer 🙏🙏🙏

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