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Debanjana Adhikari posted an Question
May 30, 2020 • 03:35 am 30 points
  • CSIR NET
  • Physical Sciences

Why outer product taken??

Q6. (A) In a system consisting of two spin particles labeled 1 and 2, let S=G and s= denote the corresponding spin operators. Here d=lo,.0,,o.) and Oxy are the three Pauli matrices. In the standard basis the matrices for the operators Ss and s's are respectively, ) o 6 ) (0 10 0 (c)00i 0h|0 0 -i 0 0- O 0 0 0) (0-i 0 0 d 00 0h|i 0 0 0 4 0 00-il 4 |0 0 0 1 o 0i 0 o o1o Ans: (c) Head office fiziks, H.No. 40-D, G.F, Jia Sarai, Near IIT, Hauz Khas, New Delhi-16 Phone: 011-26865455/+91-9871145498 Branch office Anand Institute of Mathematics, 28-B/6, Jia Sarai, Near IT Hauz Khas, New Delhi-16 Website: www.physicsbyfiziks.com Email: fiziks.physics@gmail.com fiziks fizi Institute for NET/JRF, GATE, IT-JAM, JEST, TIFR and GRE in PHYSICAL SCIENCES Solution: S's- -1 0 0 0 0 - 0 spis- 0 (B) These two operators satisfy the relation (a)ss,ss}=s'sa) (ssss]-1s'se () Ss.ss-0 Ans: (d) Solution: We have matrix Ss and Ss from question 6(A) so commutation is given by sPs s9se]-o.

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    Dhairya sharma

    reason is that we have to super impose a metrix to an element.

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    it will help u.

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    we will use condition of imposing of matrix

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    Ruby negi best-answer

    outerproduct is taken because Sx(1),Sy(2) belongs to different Hilbert space that's why for finding the product of Sx(1) and Sy(2) they did outerproduct .. if Sx(1) multiple with Sy(1) then you have to do inner product....

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    for any doubt u can ask.

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