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Nitisha Pandey posted an Question
January 23, 2021 • 20:51 pm 30 points
  • IIT JAM
  • Mathematics (MA)

01.52 2 s.a. = 2txy + 1dx 0 36x+1d(36x* +1) 36 0 146 4 du 36 145 2u 36 3 (1453/2 1) 54 = 101.52 where u = 36x2 + 1

explain this 1.52 2 S.A. = 2txy + 1dx 0 36x+1d(36x* +1) 36 0 146 4 du 36 145 2u 36 3 (1453/2 1) 54 = 101.52 where u = 36x2 + 1

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  • Priyadarshan Choursiya best-answer

    there is printing mistake, in third line root(u) comes, not root4. if you don't understand that method then first find d(36xx+1) = 72x dx then for solving substitute 36xx+1 = u

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    please sand. . solution in written

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