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Sanjana Barnwal posted an Question
June 26, 2021 • 03:25 am 5 points
  • IIT JAM
  • Mathematics (MA)

1+3+3 +... + (2n-1)_ lim- n

1+3+3 +... + (2n-1)_ lim- n solve this question from real analysis

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    Jagat Chaudhary Best Answer

    there is a mistake in this question .. for numerator part it should be 1+3+5+...+(2n-1) which is an ap with n terms having the sum n^2 hence numerator and denominator are same =n^2 hence the value of limit is 1

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