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Subhashit kumar Asked a Question
December 28, 2019 4:08 ampts 15 pts
  • IIT JAM
  • Chemistry (CY)

= 1.30 V, Quinhydrone will be: At pH = 2, E. Quinhydrone 3. O OH +2H+2e O OH 1.36 V 1.42 V (B) (D) 1.30 V 1.20 V (A) (C)

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  • Anonymous User thankyou
    use the nernst equation ....... Ecell = E°cell - 0.0591/2 log[H+]2 = 1.30 - 0.0591/2 log[10^(-2)]^2. = 1.4182 ~ 1.42
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