Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Gunjan Best Answer
thoda bada answer h darna mt , dhyan se padho samaj aa jaega.... see, sbse phle ye smjo k har heme group k ander iron hota h, jiske 4 corners pe nitrogen lge hote h (histidine wale) ye sab heme groups ek dusre k sath protein chains k through connected hote hain mtlb har ek heme dusre heme k sath ek trah ka protein chain ka salt bridge bna k reside kr ri h, jis wajah se inme bhot thight packing hoti h , hence isko tensed state kehte h ab jab o2 heme me lagne k lie ayega.... to heme ki 4 position to phle e N ne occupy ki hui thi... to 02 fifth position pe lgega..... pr kyuki heme ka structe tensed tha (uper smjaya) islie o2 ki addition mushkil hogi to heme sochta h... kyu na m apne salt bridge tod dun... jis se mera structure tensed na reh k relaxed ho jae , taki o2 asani se jud sake.... hence jaise e first o2 judega salt bridge break honge Or heme ki state tensed na rehke relaxed ho jaegi... therefore ab iske baad jitne b o2 aenge vo asani se jud paenge.. yhi cooperative effect hota h... ki first o2 ki addition mushkil, 2nd o2 ki addition asan, due to change in state of heme from tensed to relaxed hence answer is option b, state to chnge hua hi h, also intially fe tensed state me tha (domed,) to size choti thi... ab relaxed state me h (planar) to size bada hogya,