Roni posted an Question
January 19, 2021 • 12:57 pm 30 points
  • IIT JAM
  • Chemistry (CY)

1 thermodynamics please answer my question as soon as possible to

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    Dinesh khalmaniya 1 best-answer

    option A Explanation- change in enthalpy = ms delta T here delta T = 100-50 = 50 Specific heat of H2O = 4.18 j/gram. °C so change in enthalpy = 100 × 4.18× 50 = 20.9 KJ

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