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10 g of hydrogen and 64 g of oxygen were kept in a steel vessel and exploded. moles of water produced in this reaction will be (a) 2 (c) 8 (b) 4 (d) 10
10 g of hydrogen and 64 g of oxygen were kept in a steel vessel and exploded. Moles of water produced in this reaction will be (a) 2 (c) 8 (b) 4 (d) 10
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Priyanshu kumar
just balance the equation...and according find the mole of water produced
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Dinesh khalmaniya 1
hope this will help you 🙏
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Dinesh khalmaniya 1
![best-answer]()
4 mole
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Dinesh khalmaniya 1
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video solution https://doubtnut.com/question-answer-chemistry/10g-of-hydregoen-and-64g-of-oxygen-were-filled-in-a-steel-veasel-and-exploded-amount-of-water-produc-12972832
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Priyanshu kumar
hope it helps u😊🙏
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Priyanshu kumar Best Answer
https://doubtnut.com/question-answer-chemistry/10g-of-hydregoen-and-64g-of-oxygen-were-filled-in-a-steel-veasel-and-exploded-amount-of-water-produc-12972832 see this video solution keerthi
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Dinesh khalmaniya 1
The balanced equation for this reaction is as follows: 2H₂ + O₂ -------> 2H₂O Find the moles of the reacting gases. 10g of hydrogen moles = mass/molar mass = 10g / 2 = 5 moles 64g of oxygen mass/molar mass moles = 64/32 = 2 moles The mole reaction for the equation above is H₂ : O₂ is 2 :1 Therefore 5 moles of H₂ will require 2.5 moles of oxygen - this makes oxgen the limiting reagent. We therefore use the moles of oxygen to find those of H₂O: mole ratio O₂ : H₂O is 1 : 2 That means 2 moles of oxygen will produce 4 moles of H₂O
did you get it???
yaa sir I got