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Abhijeet Gaurav
Correct answer is option (C). Aa x Aa can produce three genotypes: AA, Aa and aa (Aa and aA are equivalent). The same with Bb x Bb and Cc x Cc. Since we presume they are independent, you have 3 x 3 x 3 = 27 combinations (AABBCC, AABBCc, AABBcc, AABbCC, AABbCc, AABbcc … aabbcc).