Rajni posted an Question
October 20, 2020 • 03:31 am 30 points
  • IIT JAM
  • Biotechnology (BT)

10. if the substrate concentration in an enzyme catalyzed reaction is equal to 1/2 k, the initial reaction velociy will be b. 0.33 v max a. 0.25 vmax d. 0.67 vm

10. If the substrate Concentration in an enzyme catalyzed reaction is equal to 1/2 K, the initial reaction velociy will be b. 0.33 V max a. 0.25 Vmax d. 0.67 Vmax C. 0.50 Vmax

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  • Abhijeet Gaurav best-answer

    Answer is (B). [S ] = 1/2 Km Vo = Initial Velocity Vmax = Max Velocity Vo = [S] Vmax / [S] + Km Vo = 1/2 Km × Vmax / (1/2 Km + Km) Vo = 1/2 Km × Vmax / (3/2Km) Vo = 1/3 Vmax = 0.33 Vmax

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