Rajni Kumari Asked a Question
October 19, 2020 10:01 pmpts 30 pts
10. If the substrate Concentration in an enzyme catalyzed reaction is equal to 1/2 K, the initial reaction velociy will be b. 0.33 V max a. 0.25 Vmax d. 0.67 Vmax C. 0.50 Vmax
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  • Abhijeet Gaurav thankyou
    Answer is (B). [S ] = 1/2 Km Vo = Initial Velocity Vmax = Max Velocity Vo = [S] Vmax / [S] + Km Vo = 1/2 Km × Vmax / (1/2 Km + Km) Vo = 1/2 Km × Vmax / (3/2Km) Vo = 1/3 Vmax = ...
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    Rajni Kumari
    Thankyou