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Amrutha T posted an Question
July 13, 2020 • 18:44 pm 30 points
  • IIT JAM
  • Physics (PH)

106. an isolated box is divided into two equal com apartme by a partition (see figure). one compartment co van der waals gas while the other compartmo the parti

106. An isolated box is divided into two equal com apartme by a partition (see figure). One compartment co van der Waals gas while the other compartmo The partition between the two compartment removed. After the gas has filled the entire h ss equilibrium has been achieved, which of the folt statement(s) is(are) correct? (a) Internal energy of the gas has not changed b) Intermal energy of the gas has decreased b)

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    Ghost.

    Only Option (a) is correct. since no heat is ejected or injected then the temperature will be constant, you are right option (d) can't be right, its free expansion. for option (a) see attached file, for option(d) i apologise. Wishes

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    Amrutha t

    but in answer key they also provide D along with A. but D is not possible. is't??

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    Ruby negi

    on removing partition, no heat is supplied to the system so dQ is zero and also no work is done as it is free expansion so dW is also zero, therefore using the first law of thermodynamics u can see dU is zero . therefore no change in internal energy...

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    for any doubt u could ask..

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